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a medical researcher has two petri dishes containing viruses. dish b ha…

Question

a medical researcher has two petri dishes containing viruses. dish b has a population density of 1.2 viruses per square millimeter. dish a has an area of about 2,826 square millimeters. if both petri dishes have the same population density, approximately how many viruses are in dish a? 2,355 viruses 3,391 viruses 23,550 viruses 33,912 viruses

Explanation:

Step1: Recall the density - number of viruses formula

The formula for density $d=\frac{n}{A}$, where $d$ is density, $n$ is the number of viruses and $A$ is the area. We want to find $n$, and we know $d = 1.2$ viruses per square - millimeter and $A=2826$ square - millimeters. Rearranging the formula for $n$ gives $n = d\times A$.

Step2: Calculate the number of viruses

Substitute $d = 1.2$ and $A = 2826$ into the formula $n=d\times A$. So $n=1.2\times2826 = 3391.2\approx3391$.

Answer:

3,391 viruses