Question

1. matt is practicing archery. how much work does he do if he pulls back the bow a distance of 0.75 meters if the bow has a spring constant of 1,250 n/m?

Explanation:

Step1: Recall the formula for work done in stretching a spring

The formula for work done \(W\) in stretching a spring is \(W=\frac{1}{2}kx^{2}\), where \(k\) is the spring constant and \(x\) is the displacement from the equilibrium position.

Step2: Substitute the given values into the formula

Given \(k = 1250\space N/m\) and \(x=0.75\space m\).

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Answer:

\(351.5625\space J\)