Question

subtract.
$(s^{2} + 6s + 8) - (s^{2} + 7)$

Explanation:

Step1: Remove parentheses

To subtract the two polynomials, we first remove the parentheses. When we remove the parentheses from the second polynomial, we have to distribute the negative sign to each term inside. So, \((s^2 + 6s + 8) - (s^2 + 7)\) becomes \(s^2 + 6s + 8 - s^2 - 7\).

Step2: Combine like terms

Now, we combine the like terms. The \(s^2\) terms: \(s^2 - s^2 = 0\). The constant terms: \(8 - 7 = 1\). The term with \(s\) remains as \(6s\) since there are no other like terms for it. So, combining these, we get \(0 + 6s + 1\), which simplifies to \(6s + 1\).

Answer:

\(6s + 1\)