Question

subtract.
$(0.7x^2 + 0.3x - 0.8) - (0.9x^2 + 1.3)$
$(0.7x^2 + 0.3x - 0.8) - (0.9x^2 + 1.3) = \square$

Explanation:

Step1: Distribute the subtraction

We need to distribute the negative sign to the terms inside the second parentheses. So, \((0.7x^2 + 0.3x - 0.8) - (0.9x^2 + 1.3)\) becomes \(0.7x^2 + 0.3x - 0.8 - 0.9x^2 - 1.3\).

Step2: Combine like terms for \(x^2\)

Combine the \(x^2\) terms: \(0.7x^2 - 0.9x^2 = (0.7 - 0.9)x^2 = -0.2x^2\).

Step3: Combine constant terms

Combine the constant terms: \(-0.8 - 1.3 = -2.1\).

Step4: Write the final expression

The \(x\) term remains as \(0.3x\). So putting it all together, we have \(-0.2x^2 + 0.3x - 2.1\).

Answer:

\(-0.2x^2 + 0.3x - 2.1\)