Question

solve for \x\
$3x + \frac{1}{4} = -\frac{3}{4}$
$x = \frac{\boxed{1}}{\boxed{}}$

Explanation:

Step1: Subtract $\frac{1}{4}$ from both sides

To isolate the term with \( x \), we subtract \(\frac{1}{4}\) from both sides of the equation \( 3x + \frac{1}{4} = -\frac{3}{4} \). This gives us:
\( 3x + \frac{1}{4} - \frac{1}{4} = -\frac{3}{4} - \frac{1}{4} \)
Simplifying both sides, the \(\frac{1}{4}\) and \(-\frac{1}{4}\) on the left cancel out, and on the right we have:
\( 3x = -\frac{3 + 1}{4} = -\frac{4}{4} = -1 \)

Step2: Divide both sides by 3

Now, to solve for \( x \), we divide both sides of the equation \( 3x = -1 \) by 3. This gives:
\( x = \frac{-1}{3} \)

Answer:

\( x = \boxed{-\dfrac{1}{3}} \)