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solve for p. \\(\\frac{p}{3} + 96 \\leq 97\\)

Question

solve for p.
\\(\frac{p}{3} + 96 \leq 97\\)

Explanation:

Step1: Subtract 96 from both sides

To isolate the term with \( p \), we subtract 96 from both sides of the inequality \(\frac{p}{3}+96\leq97\). This gives us \(\frac{p}{3}+96 - 96\leq97 - 96\), which simplifies to \(\frac{p}{3}\leq1\).

Step2: Multiply both sides by 3

To solve for \( p \), we multiply both sides of the inequality \(\frac{p}{3}\leq1\) by 3. This gives us \(\frac{p}{3}\times3\leq1\times3\), which simplifies to \(p\leq3\).

Answer:

\(p\leq3\)