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solve for g. 1 ≤ $\frac{g - 2}{5}$

Question

solve for g.
1 ≤ $\frac{g - 2}{5}$

Explanation:

Step1: Multiply both sides by 5

$1\times5\leq\frac{g - 2}{5}\times5$
$5\leq g - 2$

Step2: Add 2 to both sides

$5+2\leq g-2 + 2$
$7\leq g$

Answer:

$g\geq7$