QUESTION IMAGE
Question
graph
\\y = -\frac{1}{4}\sqrt{x + 2} + 1\\
⚡ Using: combining transformations · plotting points and graphing figures
Step 1: Identify the starting point (vertex)
The parent function is \( f(x) = \sqrt{x} \), which starts at \( (0,0) \).
For the transformed function:
$$ y = -\frac{1}{4}\sqrt{x + 2} + 1 $$
- Horizontal shift: The term \( x + 2 \) inside the radical shifts the graph left by \( 2 \) units.
- Vertical shift: The \( +1 \) at the end shifts the graph up by \( 1 \) unit.
Thus, the starting point of the curve is:
$$ (-2, 1) $$
Step 2: Determine the shape and direction
- Vertical reflection: The negative sign in front of the radical, \( -\frac{1}{4} \), reflects the graph vertically across the \( x \)-axis. Instead of curving upwards, the graph curves downwards.
- Vertical compression: The factor of \( \frac{1}{4} \) compresses the graph vertically, making it flatter than the standard square root curve.
Step 3: Calculate key points for plotting
Choose values of \( x \) that make the expression under the radical, \( x + 2 \), a perfect square (\( 0, 1, 4, 16 \)):
- For \( x = -2 \):
$$ y = -\frac{1}{4}\sqrt{-2 + 2} + 1 = 1 \implies (-2, 1) $$
- For \( x = -1 \):
$$ y = -\frac{1}{4}\sqrt{-1 + 2} + 1 = -\frac{1}{4}(1) + 1 = 0.75 \implies (-1, 0.75) $$
- For \( x = 2 \):
$$ y = -\frac{1}{4}\sqrt{2 + 2} + 1 = -\frac{1}{4}(2) + 1 = 0.5 \implies (2, 0.5) $$
- For \( x = 14 \):
$$ y = -\frac{1}{4}\sqrt{14 + 2} + 1 = -\frac{1}{4}(4) + 1 = 0 \implies (14, 0) $$
Step 4: Sketch the graph
- Plot the starting point at \( (-2, 1) \).
- Plot the additional points: \( (-1, 0.75) \), \( (2, 0.5) \), and the \( x \)-intercept at \( (14, 0) \).
- Draw a smooth curve starting from \( (-2, 1) \) that extends to the right, gradually curving downwards through the plotted points.
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To graph the function \( y = -\frac{1}{4}\sqrt{x + 2} + 1 \):
- Starting Point: \( (-2, 1) \)
- Direction: Curves to the right and downwards.
- Key Points to Plot:
- \( (-2, 1) \)
- \( (-1, 0.75) \)
- \( (2, 0.5) \)
- \( (14, 0) \)