Question

(\frac{x - 9}{3}=\frac{56}{x + 4})

Explanation:

Step1: Cross-multiply to eliminate fractions

$(x-9)(x+4) = 3 \times 56$

Step2: Expand both sides

$x^2 + 4x - 9x - 36 = 168$

Step3: Simplify into quadratic form

$x^2 - 5x - 204 = 0$

Step4: Factor the quadratic equation

$(x - 17)(x + 12) = 0$

Step5: Solve for x

Set each factor equal to 0: $x - 17 = 0$ or $x + 12 = 0$

Answer:

$x = 17$ or $x = -12$