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Question
\frac{b^3 - 21}{5b + 9} \text{ when } b = 3
Substitute the value of b into the expression
$$
\frac{3^3 - 21}{5(3) + 9}
$$
Simplify the numerator and denominator
$$
LATEXBLOCK0
$$
Reduce the fraction to simplest form
$$
\frac{6}{24} = \frac{1}{4}
$$
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\(\frac{1}{4}\)