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$-\frac{1}{4}x + 9 = 15$

Question

$-\frac{1}{4}x + 9 = 15$

Explanation:

Step1: Subtract 9 from both sides

To isolate the term with \( x \), we subtract 9 from both sides of the equation \( -\frac{1}{4}x + 9 = 15 \). This gives us \( -\frac{1}{4}x + 9 - 9 = 15 - 9 \), which simplifies to \( -\frac{1}{4}x = 6 \).

Step2: Multiply both sides by -4

To solve for \( x \), we multiply both sides of the equation \( -\frac{1}{4}x = 6 \) by -4. This gives us \( -4 \times (-\frac{1}{4}x) = 6 \times (-4) \). The left side simplifies to \( x \) (since \( -4 \times -\frac{1}{4} = 1 \)), and the right side simplifies to \( -24 \).

Answer:

\( x = -24 \)