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$\\frac{1}{4} + \\frac{1}{2}t = 4$

Question

$\frac{1}{4} + \frac{1}{2}t = 4$

Explanation:

Step1: Subtract 1/4 from both sides

To isolate the term with \( t \), we subtract \( \frac{1}{4} \) from both sides of the equation \( \frac{1}{4}+\frac{1}{2}t = 4 \). This gives us \( \frac{1}{2}t=4 - \frac{1}{4} \). Calculating the right - hand side: \( 4=\frac{16}{4} \), so \( \frac{16}{4}-\frac{1}{4}=\frac{15}{4} \). So now the equation is \( \frac{1}{2}t=\frac{15}{4} \).

Step2: Solve for t

To solve for \( t \), we multiply both sides of the equation \( \frac{1}{2}t=\frac{15}{4} \) by the reciprocal of \( \frac{1}{2} \), which is 2. So \( t=\frac{15}{4}\times2 \). Simplifying \( \frac{15}{4}\times2=\frac{15\times2}{4}=\frac{30}{4}=\frac{15}{2} = 7.5 \)

Answer:

\( t=\frac{15}{2} \) (or \( t = 7.5 \))