Question

find $mangle krl$.
$mangle krl= square ^{circ }$

Explanation:

Step1: Use the property of right - angle and vertical angles

We know that \(\angle HRQ\) and \(\angle LRM\) are vertical angles, so \(\angle HRQ=\angle LRM = 56^{\circ}\). Also, \(\angle KRM = 90^{\circ}\) (right - angle).

Step2: Calculate \(m\angle KRL\)

We use the formula \(m\angle KRL=m\angle KRM - m\angle LRM\). Substitute \(m\angle KRM = 90^{\circ}\) and \(m\angle LRM = 56^{\circ}\) into the formula. Then \(m\angle KRL=90^{\circ}- 56^{\circ}\).

$$m\angle KRL = 34^{\circ}$$

Answer:

\(34\)