QUESTION IMAGE
Question
evaluate.
$4^3 + (-2)^4 = \square$
Step1: Calculate \(4^3\)
\(4^3\) means 4 multiplied by itself 3 times, so \(4^3 = 4\times4\times4 = 64\).
Step2: Calculate \((-2)^4\)
\((-2)^4\) means -2 multiplied by itself 4 times. Since the exponent is even, the result will be positive. So \((-2)^4 = (-2)\times(-2)\times(-2)\times(-2)= 16\).
Step3: Add the two results together
Now we add the results from Step1 and Step2: \(64 + 16 = 80\).
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