QUESTION IMAGE
Question
differentiate.
$f(x) = x^5 - 9e^{2x}$
$f(x) = \square$
Step1: Differentiate \(x^5\)
Power rule: \(\frac{d}{dx}(x^n)=nx^{n-1}\), so \(\frac{d}{dx}(x^5)=5x^4\)
Step2: Differentiate \(-9e^{2x}\)
Chain rule: \(\frac{d}{dx}(e^{ax})=ae^{ax}\), so \(\frac{d}{dx}(-9e^{2x})=-9\times2e^{2x}=-18e^{2x}\)
Step3: Combine results
Add derivatives of both terms: \(5x^4 - 18e^{2x}\)
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\(5x^4 - 18e^{2x}\)