Question

b. \\(\log_{6} -3p - 8 = -6\\)

Explanation:

Step1: Isolate the logarithm term

Add 8 to both sides.
$\log_6(-3p) = -6 + 8$
$\log_6(-3p) = 2$

Step2: Convert to exponential form

Use $\log_b(x)=y \iff b^y=x$.
$6^2 = -3p$
$36 = -3p$

Step3: Solve for $p$

Divide both sides by -3.
$p = \frac{36}{-3}$

Answer:

$p = -12$