Question

b. $8x + y = 3$
$-8x - y = 3$

Explanation:

Step1: Add the two equations

We have the system of equations:
\[

$$\begin{cases} 8x + y = 3 \\ -8x - y = 3 \end{cases}$$

\]
Adding the left - hand sides and the right - hand sides of the two equations respectively:
\((8x + y)+(-8x - y)=3 + 3\)
Simplify the left - hand side: \(8x + y-8x - y=(8x-8x)+(y - y)=0\)
The right - hand side is \(6\). So we get \(0 = 6\).

Step2: Analyze the result

The equation \(0 = 6\) is a contradiction, which means that there are no values of \(x\) and \(y\) that can satisfy both equations simultaneously.

Answer:

No solution (the system of equations is inconsistent)