Question

1. \\(11x^2 + 5x - 5 = 0\\)

\\(a = \underline{quadquad}\quad b = \underline{quadquad}\quad c = \underline{quadquad}\\)
\\(x = \frac{-(\quad)\pm\sqrt{(\quad)^2 - 4(\quad)(\quad)}}{2(\quad)}\\)

Explanation:

Step1: Identify quadratic coefficients

Compare $11x^2 + 5x - 5 = 0$ to standard form $ax^2+bx+c=0$:
$a=11$, $b=5$, $c=-5$

Step2: Substitute into quadratic formula

The quadratic formula is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$. Substitute the values:
$x=\frac{-(5)\pm\sqrt{(5)^2-4(11)(-5)}}{2(11)}$

Answer:

$a=11$, $b=5$, $c=-5$
$x=\frac{-(5)\pm\sqrt{(5)^2-4(11)(-5)}}{2(11)}$