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4) $x^2 + x - 6$

Question

  1. $x^2 + x - 6$

Explanation:

Step1: Find two numbers

We need two numbers that multiply to \(-6\) (the constant term) and add up to \(1\) (the coefficient of \(x\)). The numbers are \(3\) and \(-2\) since \(3\times(-2)= -6\) and \(3 + (-2)=1\).

Step2: Factor the quadratic

Using the numbers from Step 1, we can rewrite the middle term and factor by grouping:

$$ LATEXBLOCK0 $$

Answer:

\((x + 3)(x - 2)\)