Question

1. $3 \times \frac{16}{15} = \frac{48}{15}$
2. $6 \times \frac{3}{14} = \frac{18}{14}$
3. $4 \times \frac{1}{9} = \frac{4}{9}$
4. $7 \times \frac{6}{17} = \frac{42}{17}$
5. $2 \times \frac{13}{3} = $

Explanation:

Step1: Solve \(3\times\frac{16}{15}\)

Multiply the integer with the numerator: \(3\times16 = 48\), so it becomes \(\frac{48}{15}\). Simplify by dividing numerator and denominator by 3: \(\frac{48\div3}{15\div3}=\frac{16}{5}\) or as a mixed number \(3\frac{1}{5}\).

Step2: Solve \(6\times\frac{3}{14}\)

Multiply 6 and 3: \(6\times3 = 18\), so \(\frac{18}{14}\). Simplify by dividing by 2: \(\frac{18\div2}{14\div2}=\frac{9}{7}\) or \(1\frac{2}{7}\).

Step3: Solve \(4\times\frac{1}{9}\)

Multiply 4 and 1: \(4\times1 = 4\), so \(\frac{4}{9}\) (already in simplest form).

Step4: Solve \(7\times\frac{6}{17}\)

Multiply 7 and 6: \(7\times6 = 42\), so \(\frac{42}{17}\) or \(2\frac{8}{17}\).

Step5: Solve \(2\times\frac{13}{3}\)

Multiply 2 and 13: \(2\times13 = 26\), so \(\frac{26}{3}\) or \(8\frac{2}{3}\).

Answer:

1. \(\frac{16}{5}\) (or \(3\frac{1}{5}\))
2. \(\frac{9}{7}\) (or \(1\frac{2}{7}\))
3. \(\frac{4}{9}\)
4. \(\frac{42}{17}\) (or \(2\frac{8}{17}\))
5. \(\frac{26}{3}\) (or \(8\frac{2}{3}\))