# Explanation: Assuming we need to find the terms of a geometric sequence. For a geometric sequence, the \(n\)-th term \(a_n=a_1\times r^{n - 1}\). ## Step1: Identify the values We are given \(a_1 = 2\) and \(r=6\). ## Step2: Use the geometric sequence formula If we want to find, say, the first few terms: - For \(n = 1\), \(a_1=2\) (given). - For \(n = 2\), \(a_2=a_1\times r=2\times6 = 12\). - For \(n = 3\), \(a_3=a_2\times r=12\times6=72\). - In general, \(a_n = 2\times6^{n - 1}\). If the problem was to find a specific term (e.g., \(n = k\)), we can substitute \(k\) into the formula \(a_k=2\times6^{k - 1}\). # Answer: If we consider the general term of the geometric sequence, it is \(a_n = 2\times6^{n - 1}\) (or specific terms can be calculated as shown above depending on the value of \(n\)).

3) a₁ = 2, r = 6

QUESTION IMAGE

Question

a₁ = 2, r = 6

Explanation:

Assuming we need to find the terms of a geometric sequence. For a geometric sequence, the \(n\)-th term \(a_n=a_1\times r^{n - 1}\).

Step1: Identify the values

We are given \(a_1 = 2\) and \(r=6\).

Step2: Use the geometric sequence formula

If we want to find, say, the first few terms:

For \(n = 1\), \(a_1=2\) (given).
For \(n = 2\), \(a_2=a_1\times r=2\times6 = 12\).
For \(n = 3\), \(a_3=a_2\times r=12\times6=72\).
In general, \(a_n = 2\times6^{n - 1}\).

If the problem was to find a specific term (e.g., \(n = k\)), we can substitute \(k\) into the formula \(a_k=2\times6^{k - 1}\).

Answer:

If we consider the general term of the geometric sequence, it is \(a_n = 2\times6^{n - 1}\) (or specific terms can be calculated as shown above depending on the value of \(n\)).