Question

1. $2 + 4 \div 4$
2. $3 + 6 - 1$
3. $6 \times (1 + 3)$
4. $(6 + 2 + 6 \times 3) \times 2$

Explanation:

Problem 3: \(2 + 4 \div 4\)

Step 1: Perform division

First, we calculate the division operation \(4 \div 4\). According to the order of operations (PEMDAS/BODMAS), division is done before addition.
\(4 \div 4 = 1\)

Step 2: Perform addition

Now we add the result of the division to 2.
\(2 + 1 = 3\)

Step 1: Perform addition

First, we add 3 and 6. Since addition and subtraction are done from left to right, we start with \(3 + 6\).
\(3 + 6 = 9\)

Step 2: Perform subtraction

Now we subtract 1 from the result of the addition.
\(9 - 1 = 8\)

Step 1: Perform operation inside parentheses

First, we calculate the expression inside the parentheses, which is \(1 + 3\).
\(1 + 3 = 4\)

Step 2: Perform multiplication

Now we multiply 6 by the result of the operation inside the parentheses.
\(6 \times 4 = 24\)

Answer:

\(3\)

Problem 6: \(3 + 6 - 1\)