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Question
- solve \\(3^{4x} > 9^{x-3}\\) for \\(x\\).
\\(x > -\frac{1}{3}\\)
\\(x = \frac{1}{3}\\)
\\(x > -1\\)
\\(x > 3\\)
Express both sides with a common base
$$
LATEXBLOCK0
$$
Set up the inequality for the exponents
$$
LATEXBLOCK1
$$
Solve for x
$$
LATEXBLOCK2
$$
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- (A) \(x > -\frac{1}{3}\)
- (B) \(x = \frac{1}{3}\)
- (C) \(x > -3\) (Correct answer)
- (D) \(x > 3\)