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2. solve \\(3^{4x} > 9^{x-3}\\) for \\(x\\). \\(x > -\\frac{1}{3}\\) \\…

Question

  1. solve \\(3^{4x} > 9^{x-3}\\) for \\(x\\).

\\(x > -\frac{1}{3}\\)

\\(x = \frac{1}{3}\\)

\\(x > -1\\)

\\(x > 3\\)

Explanation:

Express both sides with a common base

$$ LATEXBLOCK0 $$

Set up the inequality for the exponents

$$ LATEXBLOCK1 $$

Solve for x

$$ LATEXBLOCK2 $$

Answer:

  • (A) \(x > -\frac{1}{3}\)
  • (B) \(x = \frac{1}{3}\)
  • (C) \(x > -3\) (Correct answer)
  • (D) \(x > 3\)