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2) \\(\frac{2x - 2y}{25y^3x} + \frac{x - 2y}{25y^3x}\\)

Question

  1. \\(\frac{2x - 2y}{25y^3x} + \frac{x - 2y}{25y^3x}\\)

Explanation:

Step1: Combine the fractions

Since the denominators are the same ($25y^{3}x$), we can add the numerators directly:
$$\frac{(2x - 2y)+(x - 2y)}{25y^{3}x}$$

Step2: Simplify the numerator

Combine like terms in the numerator:
$2x - 2y+x - 2y=(2x + x)+(-2y-2y)=3x - 4y$
So the expression becomes:
$$\frac{3x - 4y}{25xy^{3}}$$

Answer:

$\frac{3x - 4y}{25xy^{3}}$