Question

2 + 81 ÷ 3·2 = 4

Explanation:

Step1: Check the original expression

The original expression seems to have some unclear or incorrect parts. Maybe it's a miswritten equation. Let's assume we want to solve for a variable, but the current expression \(2 + 81\div3\cdot2 = 4\) is incorrect as \(2+\frac{81}{3}\times2=2 + 27\times2=2 + 54 = 56
eq4\). If we assume there are typos, maybe a different equation. But if we consider a possible correction, maybe \(2x+8\div3\cdot2 = 4\) (assuming a variable \(x\) was missed). Let's solve \(2x+\frac{16}{3}=4\).

Step2: Subtract \(\frac{16}{3}\) from both sides

\(2x=4-\frac{16}{3}=\frac{12 - 16}{3}=\frac{-4}{3}\)

Step3: Divide by 2

\(x=\frac{-4}{3}\div2=\frac{-4}{3}\times\frac{1}{2}=\frac{-2}{3}\)

But since the original expression is unclear, maybe it's a different problem. If the original was a typo and the equation is \(2x + 8\div(3 - 2)=4\), then:

Step1: Simplify denominator

\(3 - 2 = 1\), so \(2x+8\div1 = 4\)

Step2: Simplify division

\(2x + 8 = 4\)

Step3: Subtract 8

\(2x=4 - 8=-4\)

Step4: Divide by 2

\(x=-2\)

Since the original expression is hard to interpret, but if we take the most probable typo, maybe the equation is \(2x+8\div(3 - 2)=4\), then the solution for \(x\) is \(-2\).

Answer:

If the equation is \(2x + 8\div(3 - 2)=4\), then \(x=-2\)