Question

1. $x + 20 \geq 21$

h. $5x \leq 5$

Explanation:

Step1: Solve \( x + 20 \geq 21 \)

Subtract 20 from both sides: \( x + 20 - 20 \geq 21 - 20 \)
Simplify: \( x \geq 1 \)

Step2: Solve \( 5x \leq 5 \)

Divide both sides by 5: \( \frac{5x}{5} \leq \frac{5}{5} \)
Simplify: \( x \leq 1 \)

Answer:

For \( x + 20 \geq 21 \), solution is \( x \geq 1 \); For \( 5x \leq 5 \), solution is \( x \leq 1 \)