Question

1. find the c.o.p. of $y = 3x + 1$.

Explanation:

Step1: Recall Slope-Intercept Form

The slope - intercept form of a linear equation is \(y = mx + b\), where \(m\) is the coefficient of \(x\) (the slope or the Constant of Proportionality (C.O.P.) in the case of a proportional relationship, but for a linear equation \(y=mx + b\), the slope \(m\) represents the rate of change which is also the C.O.P. when \(b = 0\); however, the formula for the C.O.P. in the linear equation \(y=mx + b\) is still given by the coefficient of \(x\)).

Step2: Identify the Coefficient of \(x\)

In the equation \(y=3x + 1\), the coefficient of \(x\) is \(3\). So, the Constant of Proportionality (C.O.P.) is the coefficient of \(x\) in the linear equation.

Answer:

The C.O.P. (Constant of Proportionality) of \(y = 3x+1\) is \(3\).