Question

1.) $-8r + 5 + 3r + (-2) = -8r + 3r + 5 + -2 =$
2.) $2x + 4 + (-8x) + (-6) =$
3.) $6x + (-4) + (-8x) + 5 =$
4.) $-7x + 8 + 2x + (-3) =$
5.) $-x + 4 + (-3x) + 8 =$
6.) $3x + 5 + (-7x) + 4 =$

Explanation:

Step1: Simplify like terms (r terms and constants) for problem 1

For \(-8r + 5 + 3r + (-2)\), combine the \(r\) terms: \(-8r+3r=-5r\), and combine the constant terms: \(5 + (-2)=3\). So the result is \(-5r + 3\).

Step2: Simplify like terms (x terms and constants) for problem 2

For \(2x + 4+(-8x)+(-6)\), combine \(x\) terms: \(2x+(-8x)=-6x\), combine constants: \(4+(-6)=-2\). Result: \(-6x - 2\).

Step3: Simplify like terms for problem 3

For \(6x+(-4)+(-8x)+5\), \(x\) terms: \(6x+(-8x)=-2x\), constants: \(-4 + 5 = 1\). Result: \(-2x+1\).

Step4: Simplify like terms for problem 4

For \(-7x + 8+2x+(-3)\), \(x\) terms: \(-7x+2x=-5x\), constants: \(8+(-3)=5\). Result: \(-5x + 5\).

Step5: Simplify like terms for problem 5

For \(-x + 4+(-3x)+8\), \(x\) terms: \(-x+(-3x)=-4x\), constants: \(4 + 8 = 12\). Result: \(-4x+12\).

Step6: Simplify like terms for problem 6

For \(3x + 5+(-7x)+4\), \(x\) terms: \(3x+(-7x)=-4x\), constants: \(5 + 4 = 9\). Result: \(-4x + 9\).

Answer:

1. \(-5r + 3\)
2. \(-6x - 2\)
3. \(-2x + 1\)
4. \(-5x + 5\)
5. \(-4x + 12\)
6. \(-4x + 9\)