QUESTION IMAGE
Question
match the given slope (m) and y-intercept (b) with the equation of the line in slope-intercept form.
slope, m = 2. y-intercept, b = 5
slope, m = 3. y-intercept, b = 7
slope, m = 25. y-intercept, b = 0
slope, m = 12. y-intercept, b = 0
slope, m = 10. y-intercept, b = 15
drag & drop the answer
y = 12x
y = 25x
y = 10x + 15
y = 2x + 5
y = 3x + 7
The slope - intercept form of a line is given by the formula \(y = mx + b\), where \(m\) is the slope and \(b\) is the \(y\) - intercept. We will use this formula to match each pair of \(m\) and \(b\) with the corresponding equation.
Step 1: For \(m = 2\) and \(b = 5\)
Using the slope - intercept form \(y=mx + b\), substitute \(m = 2\) and \(b = 5\) into the formula.
We get \(y=2x + 5\).
Step 2: For \(m = 3\) and \(b = 7\)
Substitute \(m = 3\) and \(b = 7\) into the formula \(y=mx + b\).
We have \(y = 3x+7\).
Step 3: For \(m = 25\) and \(b = 0\)
Substitute \(m = 25\) and \(b = 0\) into \(y=mx + b\). Since \(b = 0\), the equation becomes \(y=25x+0=25x\).
Step 4: For \(m = 12\) and \(b = 0\)
Substitute \(m = 12\) and \(b = 0\) into \(y=mx + b\). Since \(b = 0\), the equation is \(y = 12x+0=12x\).
Step 5: For \(m = 10\) and \(b = 15\)
Substitute \(m = 10\) and \(b = 15\) into \(y=mx + b\).
We obtain \(y=10x + 15\).
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- Slope, \(m = 2\), \(y\) - intercept, \(b = 5\) \(\longleftrightarrow\) \(y = 2x+5\)
- Slope, \(m = 3\), \(y\) - intercept, \(b = 7\) \(\longleftrightarrow\) \(y=3x + 7\)
- Slope, \(m = 25\), \(y\) - intercept, \(b = 0\) \(\longleftrightarrow\) \(y = 25x\)
- Slope, \(m = 12\), \(y\) - intercept, \(b = 0\) \(\longleftrightarrow\) \(y=12x\)
- Slope, \(m = 10\), \(y\) - intercept, \(b = 15\) \(\longleftrightarrow\) \(y = 10x+15\)