Question

masako measures a circuit at 12 v and 2 a. using ohms law, what can he calculate for the circuit?
resistance (ω)
resistance (o)
current (i)
current (ω)

Explanation:

Ohm's law is \( V = IR \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance. Given \( V = 12 \, \text{V} \) and \( I = 2 \, \text{A} \), we can rearrange Ohm's law to \( R=\frac{V}{I} \) to calculate resistance. The unit of resistance is ohms (\(\Omega\)). Current is already given (2 A), so we can't calculate current here. Also, resistance's unit is \(\Omega\), not \(O\), and current's unit isn't \(\Omega\). So the correct option is the one for calculating resistance with unit \(\Omega\).

Answer:

A. resistance (\(\Omega\))