QUESTION IMAGE
Question
marty sketches triangle def on the coordinate plane. he then sketches triangle def on the same plane. what is the scale factor going from def to def?
Step1: Recall the formula for scale factor
The scale factor \(k\) for a dilation from a pre - image (triangle \(DEF\)) to an image (triangle \(D'E'F'\)) with a center of dilation at the origin \((0,0)\) is given by \(k=\frac{x_{image}}{x_{pre - image}}\) (or \(\frac{y_{image}}{y_{pre - image}}\)) for corresponding points.
Step2: Choose a pair of corresponding points
Let's use point \(F(9,6)\) (pre - image) and \(F'(6,4)\) (image).
For the \(x\) - coordinates: \(k=\frac{x_{F'}}{x_{F}}\), substituting \(x_{F'}=6\) and \(x_{F}=9\), we get \(k = \frac{6}{9}=\frac{2}{3}\).
For the \(y\) - coordinates: \(k=\frac{y_{F'}}{y_{F}}\), substituting \(y_{F'}=4\) and \(y_{F}=6\), we get \(k=\frac{4}{6}=\frac{2}{3}\).
We can also check with point \(E(6, - 3)\) and \(E'(4,-2)\).
For the \(x\) - coordinates: \(k=\frac{x_{E'}}{x_{E}}=\frac{4}{6}=\frac{2}{3}\).
For the \(y\) - coordinates: \(k=\frac{y_{E'}}{y_{E}}=\frac{-2}{-3}=\frac{2}{3}\).
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The scale factor is \(\frac{2}{3}\)