Question

in martians, antennae head (a) dominates smooth heads (a). if i were to cross a heterozygous antenna headed individual with another heterozygous antenna headed individual, what would be the chance that the offspring would turn out to be smooth headed?

○ 100%
○ 25%
○ 50%
○ 100%

Explanation:

Step1: Identify Genotypes

Heterozygous individuals have genotype \( Aa \). So both parents are \( Aa \).

Step2: Set Up Punnett Square

The possible gametes from each parent are \( A \) and \( a \). The Punnett square is:

	\( A \)	\( a \)
\( a \)	\( Aa \)	\( aa \)

Step3: Determine Smooth - Headed Genotype

Smooth - headed (recessive) is \( aa \). From the Punnett square, out of 4 possible offspring genotypes (\( AA, Aa, Aa, aa \)), 1 is \( aa \).

Step4: Calculate Probability

The probability is \( \frac{1}{4}= 25\% \).

Answer:

25% (The option corresponding to 25% among the given options, e.g., if the option with 25% is labeled as the second option, then "2. 25%")