Question

4 mark for review the function f is defined by $f(x) = \frac{1}{10}x - 2$. what is the y-intercept of the graph of $y = f(x)$ in the xy-plane? a $(-2, 0)$ b $(0, -2)$ c $(0, \frac{1}{10})$ d $(\frac{1}{10}, 0)$

Explanation:

Step1: Recall y-intercept definition

The y - intercept of a graph is the point where the graph intersects the y - axis. On the y - axis, the x - coordinate is 0. So, to find the y - intercept of the function \(y = f(x)=\frac{1}{10}x - 2\), we set \(x = 0\) and solve for \(y\).

Step2: Substitute \(x = 0\) into the function

Substitute \(x = 0\) into \(y=\frac{1}{10}x - 2\). We get \(y=\frac{1}{10}(0)-2\). Since \(\frac{1}{10}(0) = 0\), then \(y=0 - 2=-2\).

Step3: Determine the y - intercept point

Since \(x = 0\) and \(y=-2\), the y - intercept is the point \((0,-2)\).

Answer:

B. \((0, - 2)\)