Question

this map shows that the airports in tallahassee (tlh) and orlando (mco) lie on parallel latitude lines. the flight path from tallahassee to orlando forms a 37° angle with the latitude line through tallahassee.
if the same flight path is used for the return trip, which angle will be formed by the flight path and the latitude line through orlando?
37°
53°
127°
143°

Explanation:

Step1: Use the property of parallel lines and transversal

Since the latitude lines are parallel, the flight path acts as a transversal. The angle formed at TLH (\(37^{\circ}\)) and the angle at MCO are alternate - interior angles. But wait, no. Wait, if we consider the straight - line property of the flight path. The sum of the angle at TLH (\(37^{\circ}\)) and the angle at MCO with respect to the parallel latitude lines: we know that the angle between the flight path and the latitude line at TLH is \(37^{\circ}\). The angle between the flight path and the latitude line at MCO (for the return trip) forms a linear - pair - like relationship (because of the parallel lines). The angle we want (\(\theta\)) and \(37^{\circ}\) are supplementary (since the lines are parallel and the flight path is a transversal, and for the return - trip angle calculation, using the property that the sum of angles on the same side of a transversal with respect to parallel lines is \(180^{\circ}\) when considering the "zig - zag" of the flight path).
\(\theta=180^{\circ}-37^{\circ}\)

Step2: Calculate the angle

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Answer:

\(143^{\circ}\)