Question

a man is heterozygous for sickle cell anemia and homozygous dominant for familial hypercholesterolemia. knowing that these genes are located on different chromosomes and using the information below, predict the possible sperm.
sickle cell anemia
a=normal hemoglobin
a=abnormal hemoglobin (sickle cell)
b=familial hypercholesterolemia (abnormal ldl protein receptor)
b=normal ldl protein receptor)
a ab
b ab and ab
c ab and ab
d aa and bb

Explanation:

Step1: Determine the genotype

The man is heterozygous for sickle - cell anemia (\(Aa\)) and homozygous dominant for familial hypercholesterolemia (\(BB\)). So his genotype is \(AaBB\).

Step2: Use the law of independent assortment

For the \(Aa\) gene pair, the possible alleles in gametes are \(A\) and \(a\). For the \(BB\) gene pair, the only allele in gametes is \(B\).
Combining these using the law of independent assortment (since genes are on different chromosomes), the possible sperm genotypes are \(AB\) and \(aB\).

Answer:

C. \(AB\) and \(aB\)