Question

1. machine trades a \\( \frac { 5 } { 16 } \\) -in. twist drill with a periphery speed of 50.0 ft/min has a cutting speed of 611 rpm (revolutions per minute). convert this speed to rps (revolutions per second) and round to one decimal place.

Explanation:

Step1: Convert minutes to seconds

Since \(1\) minute \( = 60\) seconds. Let \(x\) be the speed in revolutions per second. We know that the conversion formula is \(x=\frac{\text{rpm}}{60}\).
Given \(\text{rpm} = 611\).

Step2: Calculate the value

Substitute \(\text{rpm}=611\) into the formula \(x = \frac{611}{60}\).

$$x=\frac{611}{60}\approx10.2$$

Answer:

\(10.2\) rps