Question

ma.912.ar.1.2

1. rewrite the formula s = a + lw for w in terms of s.

a w = (s - a)/l
c w = s/l - a
b w = s/l + a
d w = (a - s)/l

1. the velocity v that an object r units from earth’s center must have to escape earth’s gravity is given by v² = 2gm/r, where g is a constant. solve for the object’s mass m.

a m = 2r/v²g
c m = 2g/v²r
b m = v²r/2g
d m = 2gr/v²

1. the volume v of a square pyramid is given by the formula v = 1/3s²h.

part a solve for the height h.
a h = 1/3vs²
c h = s²/3v
b h = v/3s²
d h = 3v/s²
part b find the height of a square pyramid with v of 60 cm³ and base side length s of 6 cm. ( ) cm

Explanation:

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Step1: Isolar la variable w

Comenzamos con la ecuación $s = a+ lw$. Restamos $a$ de ambos lados: $s - a=lw$.

Step2: Despejamos w

Dividimos ambos lados por $l$: $w=\frac{s - a}{l}$.

Step1: Isolar la variable M

Comenzamos con $v^{2}=\frac{2GM}{r}$. Multiplicamos ambos lados por $r$: $v^{2}r = 2GM$.

Step2: Despejamos M

Dividimos ambos lados por $2G$: $M=\frac{v^{2}r}{2G}$.

Step1: Isolar la variable h

Comenzamos con $V=\frac{1}{3}s^{2}h$. Multiplicamos ambos lados por $3$: $3V = s^{2}h$.

Step2: Despejamos h

Dividimos ambos lados por $s^{2}$: $h=\frac{3V}{s^{2}}$.

Answer:

A. $w=\frac{s - a}{l}$

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