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Question
log (1000y)
Step1: Apply log product rule
The logarithm of a product is the sum of the logarithms, so $\log(1000y) = \log(1000) + \log(y)$.
Step2: Evaluate $\log(1000)$
Since $10^3 = 1000$, $\log(1000) = 3$ (assuming base 10 logarithm, which is common if not specified).
Step3: Combine results
Substitute back to get $\log(1000y) = 3 + \log(y)$.
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$3 + \log(y)$ (or $\log(y) + 3$)