Question

1. a little boy pushes a wagon with his dog in it. the mass of the dog and wagon together is 45 kg. the wagon accelerates at 0.85 m/s2. what force is the boy pulling with? 38.25 n 52.94 n 018 n 9.81 m/s*2

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration.

Step2: Substitute the given values

Given \(m = 45\space kg\) and \(a=0.85\space m/s^{2}\). Substitute into \(F = ma\): \(F=(45)(0.85)\).

Step3: Calculate the force

\(F = 45\times0.85=38.25\space N\)

Answer:

A. \(38.25\space N\)