Question

(d) list the possible genotypes and phenotypes for the kids. (e) what is the probability of kids with squarepants? __ % (f) what is the probability of kids with roundpants? % 5. spongebob’s aunt and uncle, spongewilma and spongewilbur had children. wilma is believed to be heterozygous for her round eye shape, while wilbur’s family brags that they are a pure line. complete the punnett square to show the possibilities that would result if they had children. (a) give the genotype for each person. wilma - wilbur - (b) complete the punnett square to show the possibilities that would result if they had children. (c) list the possible genotypes and phenotypes for the kids. (d) what is the probability that the kids would have round eyes? % (e) what is the probability that the kids would be oval eyes? __ % 6. spongebob’s mother is so proud of her son and his new wife, spongesusie, as they are expecting a little sponge. she knows that they have a 50% chance of having a little roundpants, but is also hoping the new arrival will be blue (a recessive trait) like spongesusie and many members of her family. if spongebob is heterozygous for his yellow body color, what are the chances that the baby sponge will be blue? create a punnett square to help you answer this question. t. trimpe 2003 http://sciencespot.net/

Explanation:

Step1: Identify Genotypes (Assume Round Eyes is Dominant, Let's say allele R for round, r for other; Wilma is heterozygous (Rr), Wilbur is pure line (RR as pure round eyes line))

Wilma: \( Rr \), Wilbur: \( RR \)

Step2: Create Punnett Square

	\( R \)	\( R \)
\( r \)	\( Rr \)	\( Rr \)

Step3: List Genotypes and Phenotypes

Genotypes: \( RR \), \( Rr \); Phenotypes: All round eyes (since \( R \) is dominant)

Step4: Calculate Probabilities (for part d, e, f - assuming round eyes is what's asked, but let's focus on eye shape first)

For round eyes: All 4 squares have round eyes (RR or Rr), so probability 100%. For other eye shapes (if any), 0%. For the body color part (SpongeBob is heterozygous yellow, let's say Yy, SpongeSusie - wait, the body color part is in question 6. Wait, question 5 is about eye shape. Let's correct: Wait, the problem has two parts: 5 about eye shape (Wilma and Wilbur) and 6 about body color (SpongeBob and SpongeSusie). Let's handle question 5a - e first.

5a: Wilma (heterozygous round eyes) - \( Rr \), Wilbur (pure line round eyes) - \( RR \)
5b: Punnett square as above.
5c: Genotypes: \( RR \), \( Rr \); Phenotypes: Round eyes (all)
5d: Probability of round eyes: \( \frac{4}{4} = 100\% \)
5e: Probability of oval eyes (if oval is recessive, but since Wilbur is RR and Wilma is Rr, no rr, so 0%

For question 6: SpongeBob is heterozygous yellow (Yy), SpongeSusie - blue is recessive (yy, since blue is recessive). Punnett square:

	\( Y \)	\( y \)
\( y \)	\( Yy \)	\( yy \)

Probability of blue (yy): \( \frac{2}{4} = 50\% \)

Answer:

For question 5 (eye shape):
a. Wilma: \( Rr \), Wilbur: \( RR \)
b. Punnett square as above.
c. Genotypes: \( RR \), \( Rr \); Phenotypes: Round eyes
d. Probability of round eyes: 100%
e. Probability of oval eyes: 0%

For question 6 (body color):
Probability of blue baby: 50%