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lines (ell), (m), and (n) are parallel and cut by transversal (p). ente…

Question

lines (ell), (m), and (n) are parallel and cut by transversal (p).

enter the values of (x) and (y).

the value of (x) is (27)

Explanation:

Step1: Use the property of consecutive interior angles

Since lines \(l\) and \(m\) are parallel and cut by transversal \(p\), the sum of the consecutive - interior angles is \(180^{\circ}\).
So, \(108+(3x - 6)=180\).
Simplify the left - hand side: \(108+3x-6 = 3x + 102\).
Then the equation becomes \(3x+102 = 180\).
Subtract \(102\) from both sides: \(3x=180 - 102\), \(3x = 78\).
Divide both sides by \(3\): \(x=\frac{78}{3}=26\).

Step2: Use the property of corresponding angles

Since lines \(l\) and \(n\) are parallel and cut by transversal \(p\), the corresponding angles are equal.
The angle of \(108^{\circ}\) and \((2y)^{\circ}\) are supplementary (they form a linear pair with the angle that is corresponding to \(108^{\circ}\)).
Another way is to use the property that the angle adjacent to \(108^{\circ}\) (which is \(180 - 108=72^{\circ}\)) and \((2y)^{\circ}\) are corresponding angles. So \(2y=72\).
Divide both sides by \(2\): \(y = 36\).

Answer:

The value of \(x\) is \(26\) and the value of \(y\) is \(36\).