Question

lets simplify.
$x^2 - 8x + 18 = 0$
$x = \frac{\square \pm \sqrt{\square - \square}}{\square}$

Explanation:

Step1: Recall quadratic formula

For \(ax^2 + bx + c = 0\), \(x=\frac{-b\pm\sqrt{b^2 - 4ac}}{2a}\).
Here, \(a = 1\), \(b=-8\), \(c = 18\).

Step2: Identify -b

\(-b=-(-8)=8\).

Step3: Identify \(b^2\)

\(b^2=(-8)^2 = 64\).

Step4: Identify \(4ac\)

\(4ac = 4\times1\times18=72\).

Step5: Identify \(2a\)

\(2a=2\times1 = 2\).

Answer:

\(x=\frac{8\pm\sqrt{64 - 72}}{2}\) (So the blanks are filled with 8, 64, 72, 2 respectively in order)