Question

lesson 2.5 review - solving rational equations ① factor, lcm (lco) ① \\(\frac{x}{(x + 1)} + \frac{3x + 4}{(x + 1)} = \frac{3}{1} \frac{(x + 1)}{(x + 1)}\\) created with doceri multiple-choice question therefore, you should be able to identify that our lcd at this moment is (x - 1)(1), which is basically x - 1 (x + 1)(1), which is basically x + 1 (x + 1)(x + 1) rewatch

Explanation:

Step1: Identify denominators

The rational equation has denominators \((x + 1)\), \((x + 1)\), and \(1\) (since \(\frac{3}{1}\) and \(\frac{3(x + 1)}{1(x + 1)}\) have denominator \(1\) and \((x + 1)\) respectively).

Step2: Find LCD

The least common denominator (LCD) is the least common multiple (LCM) of the denominators. The denominators are \((x + 1)\) and \(1\). The LCM of \((x + 1)\) and \(1\) is \((x + 1)\times1=(x + 1)(1)\).

Answer:

B. \((x + 1)(1)\), which is basically \(x + 1\)