Question

the length of a rectangle is twice its width. if the perimeter of the rectangle is 48 in, find its length and width. length: in width: in

Explanation:

Step1: Define variables

Let width = $w$, length = $2w$

Step2: Use perimeter formula

Perimeter = $2(length + width) = 2(2w + w) = 6w$

Step3: Solve for w

$6w = 48 \implies w = 8$

Step4: Find length

Length = $2w = 2×8 = 16$

Answer:

length: 16 in
width: 8 in