Question

(left(-\frac{7}{4} div left(\frac{14}{3}
ight)
ight) \times -\frac{1}{2})

Explanation:

Step1: Simplify the division

Recall that dividing by a fraction is multiplying by its reciprocal. So, \(-\frac{7}{4} \div \frac{14}{3}=-\frac{7}{4} \times \frac{3}{14}\). Simplify the numerators and denominators: 7 and 14 have a common factor of 7, so \(-\frac{1}{4} \times \frac{3}{2}=-\frac{3}{8}\).

Step2: Multiply by the next fraction

Now multiply \(-\frac{3}{8}\) by \(-\frac{1}{2}\). The product of two negative numbers is positive, and \(3\times1 = 3\), \(8\times2 = 16\). So, \(-\frac{3}{8}\times-\frac{1}{2}=\frac{3}{16}\).

Answer:

\(\frac{3}{16}\)