Question

in lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. if the angular velocity of the ball about the elbow joint is 30.0 rad/s and the ball is 1.40 m from the elbow joint, what is the velocity of the ball? m/s

Explanation:

Step1: Recall the formula for linear velocity in circular motion

The formula for linear velocity \(v\) in circular motion is \(v = r\omega\), where \(r\) is the radius (distance from the axis of rotation) and \(\omega\) is the angular velocity.

Step2: Substitute the given values into the formula

Given \(r = 1.40\space m\) and \(\omega=30.0\space rad/s\).
Substitute into \(v = r\omega\):
\(v=(1.40\space m)\times(30.0\space rad/s)\)

Step3: Calculate the value of \(v\)

\(v = 42.0\space m/s\)

Answer:

\(42.0\)