QUESTION IMAGE
Question
lab 6. genetics introduction
name
lab day/time
datasheet
biol 111l
lab section #
list of lower case cursive letters: p = p c = c y = y t = t or t w = w or w
a = a or a s = s g = g or g b = b or b l = l r = r or r e = e
pre - lab practice: monohybrid crosses
in the space below, youll complete monohybrid punnett squares and interpret genotypes and phenotypes. follow the example in the lab intro as a guide.
- practice writing genotypes
a. when gametes a and a combine, how should the offsprings genotype be written?
b. when gametes a and a combine, how should the genotype be written?
- cross #1: goofy - colored parakeets
two heterozygous goofy - colored parakeets (gg × gg) are crossed. the g allele is dominant (goofy), and g is recessive (not goofy).
complete the punnett square:
cross: gg x gg
g g
g
g
a. how many of the offspring will show the goofy phenotype? *when asked \how many\ your answer should be written as a fraction.
b. how many will be homozygous dominant (gg)?
c. how many will be homozygous recessive (gg)?
d. what percentage of offspring are not goofy? → ______%
Step1: Determine genotypes for 1.a and 1.b
When a gamete with allele a combines with a gamete with allele A, the genotype is Aa regardless of the order of combination.
Step2: Complete Punnett - square for 2
| G | g | |
|---|---|---|
| g | Gg | gg |
Step3: Calculate Goofy phenotype offspring for 2.a
The Goofy phenotype is determined by the presence of the dominant G allele. Genotypes GG, Gg, and Gg show the Goofy phenotype. So 3 out of 4 offspring show the Goofy phenotype, which is $\frac{3}{4}$.
Step4: Determine homozygous dominant for 2.b
The homozygous - dominant genotype is GG. From the Punnett - square, there is 1 GG out of 4 offspring, so the fraction is $\frac{1}{4}$.
Step5: Determine homozygous recessive for 2.c
The homozygous - recessive genotype is gg. From the Punnett - square, there is 1 gg out of 4 offspring, so the fraction is $\frac{1}{4}$.
Step6: Calculate non - Goofy offspring for 2.d
The non - Goofy phenotype is determined by the gg genotype. There is 1 gg out of 4 offspring. As a percentage, $\frac{1}{4}\times100 = 25\%$.
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- a. Aa
b. Aa
- a. $\frac{3}{4}$
b. $\frac{1}{4}$
c. $\frac{1}{4}$
d. 25%