Question

kuta software - infinite algebr
solving proportions
solve each proportion.

1. \\(\frac{10}{8} = \frac{n}{10}\\)

1. \\(\frac{9}{6} = \frac{x}{10}\\)

1. \\(\frac{4}{3} = \frac{8}{x}\\)

Explanation:

Problem 1:

Step1: Cross - multiply the proportion

For the proportion \(\frac{10}{8}=\frac{n}{10}\), cross - multiplying gives \(8\times n = 10\times10\).

Step2: Solve for \(n\)

Simplify the right - hand side: \(8n=100\). Then divide both sides by 8: \(n = \frac{100}{8}=\frac{25}{2}=12.5\).

Step1: Cross - multiply the proportion

For the proportion \(\frac{9}{6}=\frac{x}{10}\), cross - multiplying gives \(6\times x=9\times10\).

Step2: Solve for \(x\)

Simplify the right - hand side: \(6x = 90\). Then divide both sides by 6: \(x=\frac{90}{6}=15\).

Step1: Cross - multiply the proportion

For the proportion \(\frac{4}{3}=\frac{8}{x}\), cross - multiplying gives \(4\times x = 3\times8\).

Step2: Solve for \(x\)

Simplify the right - hand side: \(4x=24\). Then divide both sides by 4: \(x = \frac{24}{4}=6\).

Answer:

\(n = 12.5\) (or \(\frac{25}{2}\))

Problem 3: