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Question
- the kinetic energy e of a moving object is given by $e = \frac{1}{2}mv^{2}$, where m is its mass in kilograms and v is its speed in meters/second.
$m = 2500$
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6b if a vehicle is traveling at 20 m/s, what is its speed in kilometers/hour to one decimal place?
$20 m/s = 72.0 km/h$
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6c if a vehicle weighing 1700 kilograms has kinetic energy $e = 166600$, at what speed is it moving?
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Step1: Substitute the values into the formula
Given \(E = \frac{1}{2}mv^{2}\), where \(E = 166600\) and \(m = 1700\). Substitute these values into the formula:
\(166600=\frac{1}{2}\times1700\times v^{2}\)
Step2: Simplify the equation
First, simplify \(\frac{1}{2}\times1700 = 850\). So the equation becomes \(166600 = 850v^{2}\).
Then, solve for \(v^{2}\): \(v^{2}=\frac{166600}{850}\)
\(v^{2}=196\)
Step3: Find the value of \(v\)
Take the square - root of both sides. Since \(v\) represents speed (a non - negative quantity), \(v=\sqrt{196}\)
\(v = 14\)
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The vehicle is moving at a speed of \(14\) meters/second.