Question

a kangaroo hopped directly toward a lake at a constant velocity for 22.5 seconds. in that time, it hopped 243 meters and passed a wallaby that was hopping at 1.5 meters per second. what was the kangaroos velocity? write your answer to the tenths place. meters per second directly toward the lake

Explanation:

Step1: Calculate the total distance

The wallaby's speed is \(1.5\) meters per second and the time is \(22.5\) seconds. The distance the wallaby hopped is \(d_{wallaby}=1.5\times22.5 = 33.75\) meters.
The total distance the kangaroo hopped is \(d = 243\) meters. So the net - distance of the kangaroo from the start (towards the lake) is \(D=243 - 33.75=209.25\) meters.

Step2: Calculate the velocity

The formula for velocity \(v=\frac{\text{displacement}}{\text{time}}\). Here, displacement \(D = 209.25\) meters and time \(t = 22.5\) seconds.
So \(v=\frac{209.25}{22.5}=9.3\) meters per second.

Answer:

\(9.3\) meters per second